A use of an overloaded function name without arguments is resolved in certain contexts to a function, a pointer to function or a pointer to member function for a specific function from the overload set. A function template name is considered to name a set of overloaded functions in such contexts. A function with type F is selected for the function type FT of the target type required in the context if F (after possibly applying the function pointer conversion) is identical to FT. [ Note: That is, the class of which the function is a member is ignored when matching a pointer-to-member-function type. — end note ] The target can be
an object or reference being initialized ([dcl.init], [dcl.init.ref], [dcl.init.list]),
the left side of an assignment,
a parameter of a function ([expr.call]),
a parameter of a user-defined operator,
the return value of a function, operator function, or conversion ([stmt.return]),
an explicit type conversion ([expr.type.conv], [expr.static.cast], [expr.cast]), or
a non-type template-parameter ([temp.arg.nontype]).
The overloaded function name can be preceded by the & operator. An overloaded function name shall not be used without arguments in contexts other than those listed. [ Note: Any redundant set of parentheses surrounding the overloaded function name is ignored ([expr.prim]). — end note ]
If the name is a function template, template argument deduction is done ([temp.deduct.funcaddr]), and if the argument deduction succeeds, the resulting template argument list is used to generate a single function template specialization, which is added to the set of overloaded functions considered. [ Note: As described in [temp.arg.explicit], if deduction fails and the function template name is followed by an explicit template argument list, the template-id is then examined to see whether it identifies a single function template specialization. If it does, the template-id is considered to be an lvalue for that function template specialization. The target type is not used in that determination. — end note ]
Non-member functions and static member functions match targets of function pointer type or reference to function type. Non-static member functions match targets of pointer to member function type. If a non-static member function is selected, the reference to the overloaded function name is required to have the form of a pointer to member as described in [expr.unary.op].
If more than one function is selected, any function template specializations in the set are eliminated if the set also contains a function that is not a function template specialization, and any given function template specialization F1 is eliminated if the set contains a second function template specialization whose function template is more specialized than the function template of F1 according to the partial ordering rules of [temp.func.order]. After such eliminations, if any, there shall remain exactly one selected function.
[ Example:
int f(double); int f(int); int (*pfd)(double) = &f; // selects f(double) int (*pfi)(int) = &f; // selects f(int) int (*pfe)(...) = &f; // error: type mismatch int (&rfi)(int) = f; // selects f(int) int (&rfd)(double) = f; // selects f(double) void g() { (int (*)(int))&f; // cast expression as selector }
The initialization of pfe is ill-formed because no f() with type int(...) has been declared, and not because of any ambiguity. For another example,
struct X {
int f(int);
static int f(long);
};
int (X::*p1)(int) = &X::f; // OK
int (*p2)(int) = &X::f; // error: mismatch
int (*p3)(long) = &X::f; // OK
int (X::*p4)(long) = &X::f; // error: mismatch
int (X::*p5)(int) = &(X::f); // error: wrong syntax for
// pointer to member
int (*p6)(long) = &(X::f); // OK
— end example ]
[ Note: If f() and g() are both overloaded functions, the cross product of possibilities must be considered to resolve f(&g), or the equivalent expression f(g). — end note ]