unique_ptr::reset
effects incorrect, too permissiveSection: 20.3.1.3.6 [unique.ptr.single.modifiers] Status: CD1 Submitter: Peter Dimov Opened: 2008-03-13 Last modified: 2016-01-28
Priority: Not Prioritized
View all other issues in [unique.ptr.single.modifiers].
View all issues with CD1 status.
Discussion:
void unique_ptr::reset(T* p = 0)
is currently specified as:
Effects: If
p == get()
there are no effects. Otherwiseget_deleter()(get())
.
There are two problems with this. One, if get() == 0
and p != 0
, the
deleter is called with a NULL
pointer, and this is probably not what's
intended (the destructor avoids calling the deleter with 0.)
Two, the special check for get() == p
is generally not needed and such a
situation usually indicates an error in the client code, which is being
masked. As a data point, boost::shared_ptr
was changed to assert on such
self-resets in 2001 and there were no complaints.
One might think that self-resets are necessary for operator=
to work; it's specified to perform
reset( u.release() );
and the self-assignment
p = move(p);
might appear to result in a self-reset. But it doesn't; the release()
is
performed first, zeroing the stored pointer. In other words, p.reset(
q.release() )
works even when p
and q
are the same unique_ptr
, and there
is no need to special-case p.reset( q.get() )
to work in a similar
scenario, as it definitely doesn't when p
and q
are separate.
Proposed resolution:
Change 20.3.1.3.6 [unique.ptr.single.modifiers]:
void reset(T* p = 0);-4- Effects: If
there are no effects. Otherwise
p ==get() == 0get_deleter()(get())
.
Change 20.3.1.4.5 [unique.ptr.runtime.modifiers]:
void reset(T* p = 0);...
-2- Effects: If
there are no effects. Otherwise
p ==get() == 0get_deleter()(get())
.