concat_view::end()
should be more constrained in order to support noncopyable iteratorsSection: 25.7.18.2 [range.concat.view] Status: New Submitter: Yaito Kakeyama & Nana Sakisaka Opened: 2024-10-13 Last modified: 2024-10-19
Priority: Not Prioritized
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Discussion:
There is a case that concat(a, b)
compiles but concat(b, a)
does not.
auto range_copyable_it = std::vector<int>{1, 2, 3}; std::stringstream ss{"4 5 6"}; auto range_noncopyable_it = std::views::istream<int>(ss); auto view1 = std::views::concat(range_copyable_it, range_noncopyable_it); static_assert(std::ranges::range<decltype(view1)>); // ok assert(std::ranges::equal(view1, std::vector{1, 2, 3, 4, 5, 6})); // ok auto view2 = std::views::concat(range_noncopyable_it, range_copyable_it); // static_assert(std::ranges::range<decltype(view2)>); // error // assert(std::ranges::equal(view2, std::vector{4, 5, 6, 1, 2, 3})); // error
The reason behind this is as follows:
Firstly, if allViews...
satisfy the std::ranges::range
concept, then concat_view
should also satisfy it.
However, if any of the Views...
have a noncopyable iterator and the last view is common_range
, the current
concat_view
fails to model a range.
For concat_view
to model a range, its sentinel must satisfy std::semiregular
, but concat_view::end()
returns a concat_view::iterator
, which is noncopyable if the underlying iterator is noncopyable. This
issue arises from the proposed implementation where the iterator uses std::variant
. Although this
specification is exposition-only, even if an alternative type-erasure mechanism is used, copying is still
required if the user attempts to copy an iterator.
To resolve the issue, concat_view::end()
can and should fallback to returning std::default_sentinel
in such cases.
Unfortunately, as a side effect, this fix would prevent concat_view
from being a common_range
in certain
situations. According to P2542R8:
concat_view
can becommon_range
if the last underlying range modelscommon_range
However, this is no longer true after applying our fix. That said, these two issues cannot be resolved
simultaneously due to implementability. Therefore, we suggest applying our fix regardless and accepting
that concat_view
will not always inherit common_range
. Note that the current draft (N4988)
does not explicitly specify when concat_view
can model common_range
, so no addition is required for
mentioning this point.
copyable
in order to model a common_iterator
.
Proposed resolution:
This wording is relative to N4993.
Modify 25.7.18.2 [range.concat.view] as indicated:
constexpr auto end() const requires (range<const Views> && ...) && concatable<const Views...>;-7- Effects: Let
is-const
betrue
for the const-qualified overload, andfalse
otherwise. Equivalent to:constexpr auto N = sizeof...(Views); if constexpr ((semiregular<iterator_t<maybe-const<is-const, Views>>> && ...) && common_range<maybe-const<is-const, Views...[N - 1]>>) { return iterator<is-const>(this, in_place_index<N - 1>, ranges::end(std::get<N - 1>(views_))); } else { return default_sentinel; }