tiny-range is not quite rightSection: 25.7.16.2 [range.lazy.split.view] Status: New Submitter: Hewill Kang Opened: 2023-01-07 Last modified: 2025-04-28
Priority: 4
View other active issues in [range.lazy.split.view].
View all other issues in [range.lazy.split.view].
View all issues with New status.
Discussion:
Currently, lazy_split_view supports input range when the element of the pattern is less than or equal to 1.
In order to ensure this condition at compile time, tiny-range constrains the type R to model
sized_range and requires (remove_reference_t<R>::size() <= 1) to be a constant expression.
sized_range does not guarantee that ranges::size will be evaluated by R::size().
For example, when disable_sized_range<R> is specialized to true or R::size() returns a non-integer-like type,
ranges::size can still compute the size by subtracting the iterator-sentinel pair when both satisfy sized_sentinel_for.
Since the lazy_split_view's iterator uses R::size() to get the constant value of the pattern,
we must ensure that this is indeed how ranges::size is calculated. Also, I think we can simplify
tiny-range with bool_constant in a way similar to LWG 3150, which removes the
introduction of require-constant.
[2023-02-01; Reflector poll]
Set priority to 4 after reflector poll.
Only matters for pathological types.
Maybe use requires bool_constant<ranges::size(r) <= 1>.
Previous resolution [SUPERSEDED]:
This wording is relative to N4917.
Modify 25.7.16.2 [range.lazy.split.view] as indicated:
namespace std::ranges {template<auto> struct require-constant; // exposition onlytemplate<class R> concept tiny-range = // exposition only sized_range<R> && requires { typename require-constant<remove_reference_t<R>::size()>; } && (remove_reference_t<R>::size() <= 1);template<input_range V, forward_range Pattern> requires view<V> && view<Pattern> && indirectly_comparable<iterator_t<V>, iterator_t<Pattern>, ranges::equal_to> && (forward_range<V> || tiny-range<Pattern>) class lazy_split_view : public view_interface<lazy_split_view<V, Pattern>> { […] }; […] }template<class R> concept tiny-range = // exposition only sized_range<R> && requires { requires bool_constant<(remove_reference_t<R>::size() <= 1)>::value; };-?- Given an lvalue
rof typeremove_reference_t<R>,Rmodelstiny-rangeonly ifranges::size(r)is evaluated byremove_reference_t<R>::size().constexpr lazy_split_view(V base, Pattern pattern);-1- Effects: : Initializes
base_withstd::move(base), andpattern_withstd::move(pattern).
[2025-04-27, Hewill provides alternative wording]
Proposed resolution:
This wording is relative to N5008.
Modify 25.7.16.2 [range.lazy.split.view] as indicated:
[Drafting note: This benefits from P2280 that a call to a member function of a non-constexpr object can be a constant expression if it does not actually access the member.
This would makeviews::lazy_split(r, span<int, 0>{})well-formed, which can be seen as an enhancement.]
namespace std::ranges {
template<auto> struct require-constant; // exposition only
template<class R>
concept tiny-range = // exposition only
sized_range<R> &&
requires (R& r) { requires bool_constant<ranges::size(r) <= 1>::value; }
requires { typename require-constant<remove_reference_t<R>::size()>; } &&
(remove_reference_t<R>::size() <= 1);
template<input_range V, forward_range Pattern>
requires view<V> && view<Pattern> &&
indirectly_comparable<iterator_t<V>, iterator_t<Pattern>, ranges::equal_to> &&
(forward_range<V> || tiny-range<Pattern>)
class lazy_split_view::view_interface<lazy_split_view<V, Pattern>> {
[…]
};
[…]
}
Modify 25.7.16.5 [range.lazy.split.inner] as indicated:
[Drafting note: We can't use
if constexpr (ranges::size(i_.parent_->pattern_) == 0)here because it is not a constant expression, and it seems more intuitive to just useranges::emptycombined with runtimeifwhich is always well-formed. Note that the PR does not seek the aggressive optimization that minimizes the instantiation as this is not the intent of the current design (for example,outer-iterator& operator++()can be specialized for the case wherePattern::size() == 0to save some O(1) comparisons), library implementations are free to optimize as it pleases.]
constexpr inner-iterator& operator++();-5- Effects: Equivalent to:
incremented_ = true; if constexpr (!forward_range<Base>) { if (ranges::empty(i_.parent_->pattern_))if constexpr (Pattern::size() == 0) {return *this; } } ++i_.current; return *this;