pair-like
types to subrange
is a silent semantic promotionSection: 25.5.4 [range.subrange] Status: C++20 Submitter: Eric Niebler Opened: 2019-09-10 Last modified: 2021-02-25
Priority: 1
View all other issues in [range.subrange].
View all issues with C++20 status.
Discussion:
Just because a pair
is holding two iterators, it doesn't mean those two iterators denote a
valid range. Implicitly converting such pair-like
types to a subrange
is
dangerous and should be disallowed.
[2019-10 Priority set to 1 and status to LEWG after reflector discussion]
[2019-11 Status to Ready after LWG discussion Friday in Belfast.]
Proposed resolution:
This wording is relative to N4830.
Modify 25.5.4 [range.subrange] as indicated:
namespace std::ranges { […]template<class T, class U, class V> concept pair-like-convertible-to = // exposition only !range<T> && pair-like<remove_reference_t<T>> && requires(T&& t) { { get<0>(std::forward<T>(t)) } -> convertible_to<U>; { get<1>(std::forward<T>(t)) } -> convertible_to<V>; };[…] template<input_or_output_iterator I, sentinel_for<I> S = I, subrange_kind K = sized_sentinel_for<S, I> ? subrange_kind::sized : subrange_kind::unsized> requires (K == subrange_kind::sized || !sized_sentinel_for<S, I>) class subrange : public view_interface<subrange<I, S, K>> { private: […] public: […]template<not-same-as<subrange> PairLike> requires pair-like-convertible-to<PairLike, I, S> constexpr subrange(PairLike&& r) requires (!StoreSize) : subrange{std::get<0>(std::forward<PairLike>(r)), std::get<1>(std::forward<PairLike>(r))} {} template<pair-like-convertible-to<I, S> PairLike> constexpr subrange(PairLike&& r, make-unsigned-like-t(iter_difference_t<I>) n) requires (K == subrange_kind::sized) : subrange{std::get<0>(std::forward<PairLike>(r)), std::get<1>(std::forward<PairLike>(r)), n} {}[…] }; […] }