*a
return an lvalue when a
is an input iterator?Section: 24.3.4 [iterator.concepts] Status: NAD Submitter: Dave Abrahams Opened: 2001-02-05 Last modified: 2016-01-28
Priority: Not Prioritized
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Discussion:
We all "know" that input iterators are allowed to produce values when dereferenced of which there is no other in-memory copy.
But: Table 72, with a careful reading, seems to imply that this can only be the case if the value_type has no members (e.g. is a built-in type).
The problem occurs in the following entry:
a->m pre: (*a).m is well-defined Equivalent to (*a).m
*a.m
can be well-defined if *a
is not a reference
type, but since operator->()
must return a pointer for
a->m
to be well-formed, it needs something to return a
pointer to. This seems to indicate that *a
must be
buffered somewhere to make a legal input iterator.
I don't think this was intentional.
Rationale:
The current standard is clear and consistent. Input iterators that return rvalues are in fact implementable. They may in some cases require extra work, but it is still possible to define an operator-> in such cases: it doesn't have to return a T*, but may return a proxy type. No change to the standard is justified.