12 Overloading [over]

12.4 Overload resolution [over.match]

12.4.2 Candidate functions and argument lists [over.match.funcs]

12.4.2.3 Operators in expressions [over.match.oper]

1
#
If no operand of an operator in an expression has a type that is a class or an enumeration, the operator is assumed to be a built-in operator and interpreted according to [expr.compound].
[Note 1:
Because ., .*, and ​::​ cannot be overloaded, these operators are always built-in operators interpreted according to [expr.compound].
?: cannot be overloaded, but the rules in this subclause are used to determine the conversions to be applied to the second and third operands when they have class or enumeration type ([expr.cond]).
— end note]
[Example 1: struct String { String (const String&); String (const char*); operator const char* (); }; String operator + (const String&, const String&); void f() { const char* p= "one" + "two"; // error: cannot add two pointers; overloaded operator+ not considered // because neither operand has class or enumeration type int I = 1 + 1; // always evaluates to 2 even if class or enumeration types exist // that would perform the operation. } — end example]
2
#
If either operand has a type that is a class or an enumeration, a user-defined operator function can be declared that implements this operator or a user-defined conversion can be necessary to convert the operand to a type that is appropriate for a built-in operator.
In this case, overload resolution is used to determine which operator function or built-in operator is to be invoked to implement the operator.
Therefore, the operator notation is first transformed to the equivalent function-call notation as summarized in Table 15 (where @ denotes one of the operators covered in the specified subclause).
However, the operands are sequenced in the order prescribed for the built-in operator ([expr.compound]).
Table 15: Relationship between operator and function call notation [tab:over.match.oper]
Subclause
Expression
As member function
As non-member function
@a
(a).operator@ ( )
operator@(a)
a@b
(a).operator@ (b)
operator@(a, b)
a=b
(a).operator= (b)
a[b]
(a).operator[](b)
a->
(a).operator->( )
a@
(a).operator@ (0)
operator@(a, 0)
3
#
For a unary operator @ with an operand of type cv1 T1, and for a binary operator @ with a left operand of type cv1 T1 and a right operand of type cv2 T2, four sets of candidate functions, designated member candidates, non-member candidates, built-in candidates, and rewritten candidates, are constructed as follows:
  • (3.1)
    If T1 is a complete class type or a class currently being defined, the set of member candidates is the result of the qualified lookup of T1​::​operator@ ([over.call.func]); otherwise, the set of member candidates is empty.
  • (3.2)
    The set of non-member candidates is the result of the unqualified lookup of operator@ in the context of the expression according to the usual rules for name lookup in unqualified function calls ([basic.lookup.argdep]) except that all member functions are ignored.
    However, if no operand has a class type, only those non-member functions in the lookup set that have a first parameter of type T1 or “reference to cv T1”, when T1 is an enumeration type, or (if there is a right operand) a second parameter of type T2 or “reference to cv T2”, when T2 is an enumeration type, are candidate functions.
  • (3.3)
    For the operator ,, the unary operator &, or the operator ->, the built-in candidates set is empty.
    For all other operators, the built-in candidates include all of the candidate operator functions defined in [over.built] that, compared to the given operator,
    • (3.3.1)
      have the same operator name, and
    • (3.3.2)
      accept the same number of operands, and
    • (3.3.3)
      accept operand types to which the given operand or operands can be converted according to [over.best.ics], and
    • (3.3.4)
      do not have the same parameter-type-list as any non-member candidate that is not a function template specialization.
  • (3.4)
    The rewritten candidate set is determined as follows:
    • (3.4.1)
      For the relational ([expr.rel]) operators, the rewritten candidates include all non-rewritten candidates for the expression x <=> y.
    • (3.4.2)
      For the relational ([expr.rel]) and three-way comparison ([expr.spaceship]) operators, the rewritten candidates also include a synthesized candidate, with the order of the two parameters reversed, for each non-rewritten candidate for the expression y <=> x.
    • (3.4.3)
      For the != operator ([expr.eq]), the rewritten candidates include all non-rewritten candidates for the expression x == y.
    • (3.4.4)
      For the equality operators, the rewritten candidates also include a synthesized candidate, with the order of the two parameters reversed, for each non-rewritten candidate for the expression y == x.
    • (3.4.5)
      For all other operators, the rewritten candidate set is empty.
    [Note 2:
    A candidate synthesized from a member candidate has its implicit object parameter as the second parameter, thus implicit conversions are considered for the first, but not for the second, parameter.
    — end note]
4
#
For the built-in assignment operators, conversions of the left operand are restricted as follows:
  • (4.1)
    no temporaries are introduced to hold the left operand, and
  • (4.2)
    no user-defined conversions are applied to the left operand to achieve a type match with the left-most parameter of a built-in candidate.
5
#
For all other operators, no such restrictions apply.
6
#
The set of candidate functions for overload resolution for some operator @ is the union of the member candidates, the non-member candidates, the built-in candidates, and the rewritten candidates for that operator @.
7
#
The argument list contains all of the operands of the operator.
The best function from the set of candidate functions is selected according to [over.match.viable] and [over.match.best].125
[Example 2: struct A { operator int(); }; A operator+(const A&, const A&); void m() { A a, b; a + b; // operator+(a, b) chosen over int(a) + int(b) } — end example]
8
#
If a rewritten operator<=> candidate is selected by overload resolution for an operator @, x @ y is interpreted as 0 @ (y <=> x) if the selected candidate is a synthesized candidate with reversed order of parameters, or (x <=> y) @ 0 otherwise, using the selected rewritten operator<=> candidate.
Rewritten candidates for the operator @ are not considered in the context of the resulting expression.
9
#
If a rewritten operator== candidate is selected by overload resolution for an operator @, its return type shall be cv bool, and x @ y is interpreted as:
  • (9.1)
    if @ is != and the selected candidate is a synthesized candidate with reversed order of parameters, !(y == x),
  • (9.2)
    otherwise, if @ is !=, !(x == y),
  • (9.3)
    otherwise (when @ is ==), y == x,
in each case using the selected rewritten operator== candidate.
10
#
If a built-in candidate is selected by overload resolution, the operands of class type are converted to the types of the corresponding parameters of the selected operation function, except that the second standard conversion sequence of a user-defined conversion sequence is not applied.
Then the operator is treated as the corresponding built-in operator and interpreted according to [expr.compound].
[Example 3: struct X { operator double(); }; struct Y { operator int*(); }; int *a = Y() + 100.0; // error: pointer arithmetic requires integral operand int *b = Y() + X(); // error: pointer arithmetic requires integral operand — end example]
11
#
The second operand of operator -> is ignored in selecting an operator-> function, and is not an argument when the operator-> function is called.
When operator-> returns, the operator -> is applied to the value returned, with the original second operand.126
12
#
If the operator is the operator ,, the unary operator &, or the operator ->, and there are no viable functions, then the operator is assumed to be the built-in operator and interpreted according to [expr.compound].
13
#
[Note 3:
The lookup rules for operators in expressions are different than the lookup rules for operator function names in a function call, as shown in the following example: struct A { }; void operator + (A, A); struct B { void operator + (B); void f (); }; A a; void B::f() { operator+ (a,a); // error: global operator hidden by member a + a; // OK: calls global operator+ }
— end note]
125)
If the set of candidate functions is empty, overload resolution is unsuccessful.
 ⮥
126)
If the value returned by the operator-> function has class type, this can result in selecting and calling another operator-> function.
The process repeats until an operator-> function returns a value of non-class type.
 ⮥