14 Templates [temp]

14.4 Type equivalence [temp.type]

Two template-ids refer to the same class or function if


template<class E, int size> class buffer { /* ... */ };
buffer<char,2*512> x;
buffer<char,1024> y;

declares x and y to be of the same type, and

template<class T, void(*err_fct)()> class list { /* ... */ };
list<int,&error_handler1> x1;
list<int,&error_handler2> x2;
list<int,&error_handler2> x3;
list<char,&error_handler2> x4;

declares x2 and x3 to be of the same type. Their type differs from the types of x1 and x4.

template<class T> struct X { };
template<class> struct Y { };
template<class T> using Z = Y<T>;
X<Y<int> > y;
X<Z<int> > z;

declares y and z to be of the same type.  — end example ]

If an expression e involves a template parameter, decltype(e) denotes a unique dependent type. Two such decltype-specifiers refer to the same type only if their expressions are equivalent ([temp.over.link]). [ Note: however, it may be aliased, e.g., by a typedef-name.  — end note ]